(x^2-x-40)^(3/4)

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Solution for (x^2-x-40)^(3/4) equation: 


D( x )

x^2-x-40 < 0

x^2-x-40 < 0

x^2-x-40 < 0

x^2-x-40 < 0

DELTA = (-1)^2-(-40*1*4)

DELTA = 161

DELTA > 0

x = (161^(1/2)+1)/(1*2) or x = (1-161^(1/2))/(1*2)

x = (161^(1/2)+1)/2 or x = (1-161^(1/2))/2

a = 1

a > 0

x in ((1-161^(1/2))/2:(161^(1/2)+1)/2)

x in (-oo:(1-161^(1/2))/2> U <(161^(1/2)+1)/2:+oo)

(x^2-x-40)^(3/4) = 0

x^2-x-40 = 0

x^2-x-40 = 0

DELTA = (-1)^2-(-40*1*4)

DELTA = 161

DELTA > 0

x = (161^(1/2)+1)/(1*2) or x = (1-161^(1/2))/(1*2)

x = (161^(1/2)+1)/2 or x = (1-161^(1/2))/2

(x-((1-161^(1/2))/2))*(x-((161^(1/2)+1)/2)) = 0

(x-((1-161^(1/2))/2))^(3/4)*(x-((161^(1/2)+1)/2))^(3/4) = 0

( x-((1-161^(1/2))/2) )

x-((1-161^(1/2))/2) = 0 // + (1-161^(1/2))/2

x = (1-161^(1/2))/2

( x-((161^(1/2)+1)/2) )

x-((161^(1/2)+1)/2) = 0 // + (161^(1/2)+1)/2

x = (161^(1/2)+1)/2

x in { (1-161^(1/2))/2, (161^(1/2)+1)/2 }

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